No two card shuffles will EVER be the same.

HungLikeJesus · 02-06-2008, 08:13 AM

I forgot to check one of the boundary values. For n = 52!, P should equal one. Instead, for n = 52!, P = (52!-1)/2, so something is not right.

Happy Monkey · 02-06-2008, 11:17 AM

Quote:

Originally Posted by HungLikeJesus

I forgot to check one of the boundary values. For n = 52!, P should equal one.

No, P will never be one. You are never guaranteed to get a match.

02-06-2008, 08:13 AM	#1
HungLikeJesus Only looks like a disaster tourist Join Date: Feb 2007 Location: above 7,000 feet Posts: 7,208	I forgot to check one of the boundary values. For n = 52!, P should equal one. Instead, for n = 52!, P = (52!-1)/2, so something is not right. __________________ Keep Your Bodies Off My Lawn SteveDallas's Random Thread Picker.

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