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Old 02-06-2008, 08:30 AM   #14
Shawnee123
Why, you're a regular Alfred E Einstein, ain't ya?
 
Join Date: Jun 2006
Posts: 21,206
Quote:
Originally Posted by HungLikeJesus View Post
I forgot to check one of the boundary values. For n = 52!, P should equal one. Instead, for n = 52!, P = (52!-1)/2, so something is not right.
Then, what is this n? Does n=52 or does n=number of shuffles?

Quote:
Originally Posted by HungLikeJesus View Post
I'd better present my logic to see if anyone disagrees.

(n*(n-1))/(2*52!) = P; solve for P, where P = probability of 2 or more matching shuffled decks in n shuffles.

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