C++ Help, Please. Thank You.

[Flint]

Happy Monkey's suggested code from post #15 also works.

Using the else condition to exit the loop, otherwise prompting for the password at the top of the loop. This is more concise.

Please enter a password: abc
Passwords must be at least 6 characters long
Please enter a password: abcdef
Passwords must include at least on digit (1-9)
Please enter a password: 123
Passwords must be at least 6 characters long
Please enter a password: abcdef
Passwords must include at least on digit (1-9)
Please enter a password: abc123
Thank you that is a valid password

Press Enter to close window...

#include<iostream>
#include<cstring>
#include<cctype>
using namespace std;
	
	//Function checks the password for length.		(a)
	bool passLength(char[]);

	//Function checks the password for a digit.		(b)
	bool containDigit(char[]);
	
	const int SIZE = 21;
	char password[SIZE];

int main()
{
	bool ok=false;
	while ( ! ok )
	{
    cout << "Please enter a password: ";
    cin.getline(password, SIZE);

    if (! passLength(password))
		{
		cout << "Passwords must be at least 6 characters long" << endl;
		} 
    else if ( ! containDigit(password) )
		{
		cout << "Passwords must include at least on digit (1-9)" << endl;
		}
    else
		{
		ok=true;
		}
  }


	cout << "Thank you that is a valid password" << endl;
	
	
	//Keep the window open until Enter key is pressed.
	cout << "\nPress Enter to close window..." << endl;
	std::cin.get();

	return 0;
}	

	bool passLength(char password[])				//(a)
{
	int lengthPass = 6;
	int length = strlen(password);
	
		if (lengthPass <= length)
			return true;
		else 
			{
			return false;
			}
}


	bool containDigit(char password[])				//(b)
{
	int index = 0;
	int length = strlen(password);
	
	for (index = 0; index < length; index++ )
	{
		if (isdigit(password[index]))
			return true;
	}
		return false;
	
}