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#1 |
Slattern of the Swail
Join Date: Jul 2004
Posts: 15,654
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flint--i've a huge crush on you.
deal. |
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#2 |
Snowflake
Join Date: Mar 2006
Location: Dystopia
Posts: 13,136
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Deal? There's 8.06581751709439e+67 different ways I could take that.
__________________
****************** There's a level of facility that everyone needs to accomplish, and from there it's a matter of deciding for yourself how important ultra-facility is to your expression. ... I found, like Joseph Campbell said, if you just follow whatever gives you a little joy or excitement or awe, then you're on the right track. . . . . . . . . . . . . . . . . . . . . . . . . . . Terry Bozzio |
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#3 |
Only looks like a disaster tourist
Join Date: Feb 2007
Location: above 7,000 feet
Posts: 7,208
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Flint, here's what I'm thinking:
There are 52! (52 factorial) ways that the first shuffle can come out. The probability of the second shuffle exactly matching the first is 1/52!. The third shuffle has a 1/52! chance of matching the first shuffle, and a 1/52! chance of matching the second shuffle, so by the third shuffle, there's a 3/52! chance of two shuffles being the same. The 4th shuffle has a 1/52! chance of matching the first shuffle, and a 1/52! chance of matching the second shuffle, 1/52! chance of matching the 3rd shuffle, so by the 4th shuffle, there's a 7/52! chance of two shuffles being the same. Etc... The question should be, "how many shuffles would be required to have an X % chance of two shuffles matching?" |
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