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Old 02-04-2008, 11:41 AM   #1
Trilby
Slattern of the Swail
 
Join Date: Jul 2004
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flint--i've a huge crush on you.


deal.
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Old 02-04-2008, 12:02 PM   #2
Flint
Snowflake
 
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Quote:
Originally Posted by Brianna View Post
deal.
Deal? There's 8.06581751709439e+67 different ways I could take that.
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Old 02-04-2008, 12:27 PM   #3
HungLikeJesus
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Flint, here's what I'm thinking:
There are 52! (52 factorial) ways that the first shuffle can come out.

The probability of the second shuffle exactly matching the first is 1/52!.

The third shuffle has a 1/52! chance of matching the first shuffle, and a 1/52! chance of matching the second shuffle, so by the third shuffle, there's a 3/52! chance of two shuffles being the same.

The 4th shuffle has a 1/52! chance of matching the first shuffle, and a 1/52! chance of matching the second shuffle, 1/52! chance of matching the 3rd shuffle, so by the 4th shuffle, there's a 7/52! chance of two shuffles being the same.

Etc...

The question should be, "how many shuffles would be required to have an X % chance of two shuffles matching?"
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