Happy Monkey's suggested code from post #15 also works.
Using the else condition to exit the loop, otherwise prompting for the password at the top of the loop. This is more concise.
Quote:
Please enter a password: abc
Passwords must be at least 6 characters long
Please enter a password: abcdef
Passwords must include at least on digit (1-9)
Please enter a password: 123
Passwords must be at least 6 characters long
Please enter a password: abcdef
Passwords must include at least on digit (1-9)
Please enter a password: abc123
Thank you that is a valid password
Press Enter to close window...
|
Code:
#include<iostream>
#include<cstring>
#include<cctype>
using namespace std;
//Function checks the password for length. (a)
bool passLength(char[]);
//Function checks the password for a digit. (b)
bool containDigit(char[]);
const int SIZE = 21;
char password[SIZE];
int main()
{
bool ok=false;
while ( ! ok )
{
cout << "Please enter a password: ";
cin.getline(password, SIZE);
if (! passLength(password))
{
cout << "Passwords must be at least 6 characters long" << endl;
}
else if ( ! containDigit(password) )
{
cout << "Passwords must include at least on digit (1-9)" << endl;
}
else
{
ok=true;
}
}
cout << "Thank you that is a valid password" << endl;
//Keep the window open until Enter key is pressed.
cout << "\nPress Enter to close window..." << endl;
std::cin.get();
return 0;
}
bool passLength(char password[]) //(a)
{
int lengthPass = 6;
int length = strlen(password);
if (lengthPass <= length)
return true;
else
{
return false;
}
}
bool containDigit(char password[]) //(b)
{
int index = 0;
int length = strlen(password);
for (index = 0; index < length; index++ )
{
if (isdigit(password[index]))
return true;
}
return false;
}