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Originally Posted by Flint
If it is a good password the function cannot return false.
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If the password going in is bad, abd the password entered in the function is good, then the function returns false, even though the password is good.
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No, man. The if condition corrects for it by not calling the function unless it is false.
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It calls it no matter what. If that first call returns false, it calls the function a second time (third if you count the loop test).
Every time you call if (!a()), you are calling a().
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The while loop doesn't correct the behavior, the while loop just exits the loop before the next iteration.
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While giving the user two more chances to change the password.