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Not being one to let a good thread die, here is another riddle... well actually a conundrum.
Two twins are born. The YOUNGER twin celebrates his birthday two days earlier than the OLDER twin. How could this be true? |
This may not be the answer you want, but... maybe they're not one anothers' twins? Meaning, each is a twin from separate pairs?
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They are twins of each other. |
a Golden Prize do I hide but neither do I have hinges, lock or side. What am I?
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Hmm. Probably something to do with being born at midnight, leap year, and/or the International Date line then....
I'd say either one was born just before midnight, and the other just after, on leap year. If not that, then the same birth times, also on leap year, but they crossed the International Date Line after the first was born (on a plane, or something). Edit: Of course, both on Feb 28th of a leap year. |
There might be two sets of twins. One set of twins was born a year or years later than the other set, minus two days.
Oct 11 1980 Oct 13 1975 |
Hm. I like HP's answer.
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HP has the kernel of the idea, but can someone set up the exact scenario that would cause the event to happen?
And Beastie, I had a couple of those today for lunch! |
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That would explain how one twin celebrates his birthday two days after the other, but what about the younger one having his birthday before the older? |
Mom had to roll across the internation dateline somewhere in there ... and New Years eve needs to play a part ... like if the older twin were born on 12/30 near midnight, then mom's hospital gurney, which is set right on the international date line, rolls over it, and just past midnight the "next" day, the younger twin could be born on 1/1 ... AND the younger twin's birthday would be earlier in the year than the older twin's.
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