I forgot to check one of the boundary values. For n = 52!, P should equal one. Instead, for n = 52!, P = (52!-1)/2, so something is not right.

Yeah I was thinking n=52????????????????????, not 52!

and I thought "n" was a letter not a number - silly me.

Then, what is this n? Does n=52 or does n=number of shuffles?

I think n=n.

lmao

You damn kids and your new math.

n represents the number of shuffles. When the decks have been shuffled 52! times (52x51x50x...x2x1), all possible combinations --- hey, I think you're right! I've been thinking about this wrong. You don't have to encounter every possible combination to get two that match. Maybe my original calculations were right. I will think about it while I shower. I hope this B&B has a lot of hot water.

Can we watch...um, er...I mean watch the mathematical genius as his mind dazzles with brilliance and...

Just give me a number so I can slap you in the face with it. I haven't met my quota for scathing remarks this morning.

Sorry, I have to be up to the big house in 10 minutes, to get the second B of this B&B.

Buttsecks and barbecue?

Well, it is Montana. Rules are rules.

After last night, I hope it's not too spicy.

I think that's the point

:lol: busting a gut

No, P will never be one. You are never guaranteed to get a match.

Yes you are, because the outcomes are limited--it's like if you have four different colors of socks, and you choose five socks. Your fifth sock must match one of the other four.