I forgot to check one of the boundary values. For n = 52!, P should equal one. Instead, for n = 52!, P = (52!-1)/2, so something is not right.
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and I thought "n" was a letter not a number - silly me.
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I think n=n.
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lmao
You damn kids and your new math. |
n represents the number of shuffles. When the decks have been shuffled 52! times (52x51x50x...x2x1), all possible combinations --- hey, I think you're right! I've been thinking about this wrong. You don't have to encounter every possible combination to get two that match. Maybe my original calculations were right. I will think about it while I shower. I hope this B&B has a lot of hot water.
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Can we watch...um, er...I mean watch the mathematical genius as his mind dazzles with brilliance and...
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Just give me a number so I can slap you in the face with it. I haven't met my quota for scathing remarks this morning.
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Buttsecks and barbecue?
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Well, it is Montana. Rules are rules.
After last night, I hope it's not too spicy. |
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:lol: busting a gut |
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Yes you are, because the outcomes are limited--it's like if you have four different colors of socks, and you choose five socks. Your fifth sock must match one of the other four.
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