The Cellar - Mental Nuts-- Can You Crack 'em?

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- - Mental Nuts-- Can You Crack 'em? (http://cellar.org/showthread.php?t=26507)

Yeah, yeah, tell it to the Judge.:rolleyes:

:)

The horse or the squirrel?

This was a good idea for a thread.

The next several nuts are just math tricks or as the Brits like to say maths trick,

whatever. I am putting all of them up along with the advertisements and then the nut nut proper. One has to remember things were different in 1921. No calculators for instance.

Quote:

Originally Posted by classicman (Post 784443)

But what did he pay for it initially?

And I'm still not done with that circular squirrel yet....

The tree is only the existential quantifier of your circular squirrel.
Take it out of the equation and the logic is obvious. ;)

I thought so as well, but I thought the answer was no he does not.
Hence the repeated question.

Yes. The hunter does not go around the squirrel. They both go around the tree but the squirrel always keeps the tree between himself and the hunter. For the hunter to go around the squirrel it would need to stay in one place on the tree.

Why? If the squirrel is ALWAYS on the tree and the hunter circles the tree ...
This must be a matter of semantics or definitions.

Quote:

Originally Posted by footfootfoot

Well you know what else? Heisenberg says both are orbiting the tree, and you can't say for certain where either one is in their orbital path at a given time. But you do know that the hunter is in a higher orbital than the squirrel, and the higher orbital plane does encircle the lower orbital plane. The more time that passes, the higher the statistical probability that the hunter has orbited the squirrel. Nyeah.

Quote:

Originally Posted by Clodfobble (Post 784572)

NO, you have to re-read the question. There is no treadmill involved. They are moving at the same rate around the same axis. The squirrel will never be encircled by the hunter. The spot where the squirrel had been will be encircled, but not the squirrel itself.

Quote:

Consider a bicycle wheel for example. The hole in the rim for the valve stem is opposite the seam of the rim. The wheel revolves around the axle. The valve stem and seam each go around the axle every revolution. They do not go around each other. They do go around the position the other previously occupied however. Compare this to a ratchet wrench. The socket is the axis, the handle goes around the axis, but the handle does not go around itself.
The squirrel always keeps the tree between himself and the hunter. The tree is the axis, the squirrel is the seam on the rim and the hunter is the valve stem.

No, the hunter does not walk around his gun. His gun is not stationary, it moves with him. He may walk around the location his gun used to be, but that is not the same as walking around his gun. Unless he has one of those special mag-lev guns that just hangs in mid air while you circumambulate around it. Otherwise, if it is a normal gun then he will be taking it with him when he walks around the tree.

And another thing, you all avoided
How I need a drink, alcoholic in nature, after the tough chapters involving quantum mechanics!

Cipher - I like that. Isn't that what Jethro Bodine used to say?

Yes, but did he affix them? Another cromulent word that is under-used these days.

and can you affix nothing to something?

The answer to #33 is yes.

The force on the pulley will be the same with two equal weights (W+W) or with a weight (W) on one side and the second side anchored to the floor.

Quote:

Originally Posted by classicman (Post 784562)

Why? If the squirrel is ALWAYS on the tree and the hunter circles the tree ...
This must be a matter of semantics or definitions.

No, it's geometry.